Ln[1-4cos^2(x)]=0

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Solution for Ln[1-4cos^2(x)]=0 equation:


Simplifying
Ln[1 + -4cos2(x)] = 0

Multiply cos2 * x
nL[1 + -4cos2x] = 0
[1 * nL + -4cos2x * nL] = 0

Reorder the terms:
[-4cnos2xL + 1nL] = 0
[-4cnos2xL + 1nL] = 0

Solving
-4cnos2xL + 1nL = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1nL' to each side of the equation.
-4cnos2xL + 1nL + -1nL = 0 + -1nL

Combine like terms: 1nL + -1nL = 0
-4cnos2xL + 0 = 0 + -1nL
-4cnos2xL = 0 + -1nL
Remove the zero:
-4cnos2xL = -1nL

Divide each side by '-4nos2xL'.
c = 0.25o-1s-2x-1

Simplifying
c = 0.25o-1s-2x-1

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